Arithmetic Questions and Answers

Q1 :

Which one of the following number is exactly divisible by 11 ?

A
  

315624

B
  

245642

C
  

415624

D
  

235641

View Answer
Correct Answer: C

415624

Description:
Q2 :

The product of two numbers is forty five and their difference is four. The sum squares of the 2 numbers is

A
  

135

B
  

240

C
  

73

D
  

106

View Answer
Correct Answer: D

106

No Description
Q3 :

The value of expression

1÷{12+13+16÷(3413)}1 div Biggl{ frac{1}{2} + frac{1}{3} + frac{1}{6} div bigg(frac{3}{4}-frac{1}{3}bigg) Biggr} is:

A
  

512frac{5}{12}

B
  

112frac{1}{12}

C
  

3037frac{30}{37}

D
  

1

View Answer
Correct Answer: C

3037frac{30}{37}

Description:

=1÷{12+13+16÷(3413)}=1div Biggl{ frac{1}{2} + frac{1}{3} + frac{1}{6} div bigg(frac{3}{4}-frac{1}{3}bigg) Biggr}

=1÷{12+13+16÷512}=1div Biggl{ frac{1}{2} + frac{1}{3} + frac{1}{6} div frac{5}{12} Biggr}

=1÷{12+13+16×125}=1div Bigg{ frac{1}{2} + frac{1}{3} + frac{1}{6} times frac{12}{5} Bigg}

=1÷{12+13+25}=3037=1div Bigg{ frac{1}{2} + frac{1}{3} + frac{2}{5} Bigg} = frac{30}{37}

Q4 :

Find the square root of 20.8849

A
  

.457

B
  

4.57

C
  

45.7

D
  

457

View Answer
Correct Answer: B

4.57

Description:

= 4.57*4.57
= 20.8849
 

Q5 :

Find the value of 36.1102.4sqrt{frac{36.1}{102.4}}

A
  

1934frac{19}{34}

B
  

1931frac{19}{31}

C
  

6.134frac{6.1}{34}

D
  

1932frac{19}{32}

View Answer
Correct Answer: D

1932frac{19}{32}

Description:

=36.1102.4=3611024=1932=sqrt{frac{36.1}{102.4}} = sqrt{frac{361}{1024}} = frac{19}{32}

Q6 :

The decimal number 0.320.overline{32} is equal to the rational number

A
  

32100frac{32}{100}

B
  

3299frac{32}{99}

C
  

30100frac{30}{100}

D
  

3199frac{31}{99}

View Answer
Correct Answer: B

3299frac{32}{99}

Description:

 Let x=0.32=0.323232...text{ Let } x = 0.overline{32} = 0.323232...

100x=32.323232...therefore 100x = 32.323232...

=32.3299x=32= 32.overline{32} Rightarrow 99x = 32

x=3299therefore x = frac{32}{99}

Q7 :

Which one of the following measures of central tendency gives greater importance to smaller and lesser importance to bigger items of a series?

A
  

Arithmetic mean

B
  

Geometric mean

C
  

Median

D
  

Mode

View Answer
Correct Answer: B

Geometric mean

Description:

Geometric mean gives the greater importance to smaller and lesser importance to bigger items of a series.

Q8 :

The mean of 5 observations x,x+2,x+4,x+6 and x+8x, x+ 2, x + 4, x + 6 text{ and } x + 8 is 11. Then the mean of last 3 observations is

A
  

11

B
  

13

C
  

15

D
  

17

View Answer
Correct Answer: B

13

Description:

Mean of the given observations

=x+4=11x=7= x + 4 = 11 Rightarrow x = 7

Required mean of the last three observations

=x+6=13= x + 6 = 13

Q9 :

The arithmetic mean of nn number is xoverline{x}. The sum of the first (n1)(n - 1) numbers is kk. The nnth number is

A
  

nx2kn overline{x} - 2k

B
  

nxkn overline{x} - k

C
  

nx+kn overline{x} + k

D
  

nx+2kn overline{x} + 2k

View Answer
Correct Answer: B

nxkn overline{x} - k

Description:

The sum of nn number =nx= n ; overline { x} ,
any given sum of (n1)th no. =k(n - 1)text{th no. } = k
 nth number =nxktherefore text{ nth number } = n ; overline{x} - k

Q10 :

 If 34frac{3}{4} of an estate is worth Rs. 90,000/-, then the value of 23frac{2}{3} of the same will be

A
  

Rs. 60,000

B
  

Rs. 65,000

C
  

Rs. 70,000

D
  

Rs. 80,000

View Answer
Correct Answer: D

Rs. 80,000

Description:

 The value of 23frac{2}{3} rd estate is =90,000×4×23×3= frac{90,000 times 4 times 2}{3 times 3}

= Rs. 80,000/-

Q11 :

Let n[X]n[text{X}] denote the number of elements in the set Xtext{X}. If for two sets A and B, nn[A] = 12, nn[B] = 30, nn[A cap B] = 25, then nn[A cup B] is equal to

A
  

25

B
  

19

C
  

17

D
  

15

View Answer
Correct Answer: C

17

Description:

Apply n(AB)=n(A)+n(B)n(AB)n(A cup B) = n(text{A}) + n(text{B}) - n(text{A} cap text{B})

Q12 :

The value of (.05×.05×.05)+(.04×.04×.04)(.05×.05)(.05×.04)+(.04×.04)frac{(.05 times .05 times .05) + (.04 times .04 times .04)}{(.05 times .05) - (.05 times .04) + (.04 times .04)} is

A
  

0.0009

B
  

0.01

C
  

0.09

D
  

0.41

View Answer
Correct Answer: C

0.09

Description:

Apply the formula a3+b3a2ab+b2=(a+b)frac{a^3 + b^3}{a^2 - ab + b^2} = (a + b)

where a=0.05 and b=0.04a = 0.05 text{ and } b = 0.04

Q13 :

If A and B are two sets, then A(AB)text{A} cap (text{A} cup text{B}) is equal to

A
  

A

B
  

B

C
  

ϕphi

D
  

A cap B

View Answer
Correct Answer: C

ϕphi

Description:

A(AB)=A(A’B’)text{A} cap (text{A} cup text{B})text{'} = text{A} cap (text{A'} cap text{B'})

=(AA’)B’=ϕB’=ϕ= (text{A} cap text{A'}) cap text{B'} = phi cap text{B'} = phi

Q14 :

Let N be the set of all natural numbers, E be the universal set, ϕphi be the null set and B be the unit set containing 0, i.e. B = {0}. If A is the subset of every set X, then A is equal to

A
  

N

B
  

B

C
  

ϕphi

D
  

E

View Answer
Correct Answer: C

ϕphi

Description:

Empty set is a subset of every set.

Q15 :

If nn is any whole number, n2(n21)n^2 (n^2 - 1) is always divisible by:

A
  

12

B
  

24

C
  

36

D
  

9

View Answer
Correct Answer: A

12

Description:

Here we can apply least value of whole no. in the place n2(n21)n^2 (n^2 - 1) except 0 and 1.

n2(n21)=22(221)=12n^2 (n^2 - 1) = 2^2 (2^2 - 1 ) = 12

Q16 :

Simplify: 75+48243sqrt{75} + sqrt{48} - sqrt{243}

A
  

0

B
  

232sqrt{3}

C
  

333sqrt{3}

D
  

434sqrt{3}

View Answer
Correct Answer: A

0

Description:

75+48243sqrt{75} + sqrt{48} - sqrt{243}

=53+4393=5sqrt{3} + 4sqrt{3} - 9sqrt{3}

=3(5+49)=sqrt{3}(5 + 4 -9)

=3×0=sqrt{3} times 0

=0=0

Q17 :

Solve the following—
0.0625+0.250= ?sqrt{0.0625} + sqrt{0.250} = text{ ?}

A
  .005
B
  0.5
C
  5
D
  None of the Above
View Answer
Correct Answer: D None of the Above
Description:

0.0625+0.250 .25+.5=.75begin{aligned} sqrt{0.0625} + sqrt{0.250} Rightarrow .25 + .5 = .75 end{aligned}

Q18 :

Solve the following equation:

8461÷11.9924.01÷510=?8461 div 11.99 - 24.01 div frac{5}{10} = ?

A
  

225

B
  

625

C
  

400

D
  

25

View Answer
Correct Answer: A

225

Description:

8461÷11.9924.01÷5108461 div 11.99 - 24.01 div frac{5}{10}

70524×20approx 705 - 24 times 20

705480approx 705 - 480

225approx 225

Q19 :

If in a grouped data median is 50 and each frequency is multiplied by 3, then the new median is—

A
  

300

B
  

150

C
  

50

D
  

None of the above

View Answer
Correct Answer: C

50

No Description
Q20 :

If 23×5=2623 times 5 = 26 and 13×8=1913 times 8 = 19, then 39×739 times 7 =

A
  

42

B
  

43

C
  

44

D
  

40

View Answer
Correct Answer: C

44

Description:

23+52=2613+82=1939+72=44begin{aligned} because quad & 23+5-2 = 26 & 13+8-2 = 19 therefore quad & 39+7-2 = 44 end{aligned}

Q21 :

What is the value of xx for which x,x+1,x+3x, x + 1, x + 3 are all prime numbers?

A
  

0

B
  

1

C
  

2

D
  

101

View Answer
Correct Answer: C

2

Description:

If x=2x = 2, then, x,x+1x, x + 1 and x+3x + 3 are all prime numbers.

Q22 :

Which of the following statements about the number 222222 is correct?

A
  

It is divisible by 3 but not divisible by 7

B
  

It is divisible by 3 and 7 but not divisible by 11

C
  

It is divisible by 2 and 7 but not divisible by 11

D
  

It is divisible by 3, 7 and 11

View Answer
Correct Answer: D

It is divisible by 3, 7 and 11

Description:

Given, number is 222222.

Here, sum of digits
= 2 + 2 + 2 + 2 + 2 + 2 = 12,
which is divisible by 3. So, given number
is divisible by 3.

Now, sum of odd terms of digits − Sum
of even terms of digits = 6 − 6 = 0,
it is divisible by 11.

Also, in a number if a digit is repeated
six times, then the number is divisible by
7, 11 and 13.

Hence, the given number is divisible by
3, 7 and 11.