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Percentage Questions and Answers

Q1 :

In an election, one of the two candidates got 40% of the total votes cast and lost by 100 votes. The total number of votes cast in the election is

A
  

400

B
  

500

C
  

600

D
  

700

View Answer
Correct Answer: B

500

Description:

100 votes = 20% of the total votes cast difference % between two candidates.
thereforeThe total number of votes cast = 500

Q2 :

A mixture of 40 litres of milk and water contains 10 p.c. of water. How much water must be added to make the water 20% in the new mixture?

A
  

3

B
  

7

C
  

10

D
  

5

View Answer
Correct Answer: D

5

Description:

90% of 40=80% of new mixture90% text{ of } 40 = 80% text{ of new mixture}

New mixture =90×4080=45 litrestext{New mixture } = frac{90 times 40}{80} = 45 text{ litres}

Water added 4540=5 litrestext{Water added } 45-40 = 5 text{ litres}

Q3 :

If 20% of a number is 7.2, then the number is

A
  

34

B
  

35

C
  

36

D
  

37

View Answer
Correct Answer: C

36

Description:

20% is 7.2

20%×5=100% , so the number is 7.2×5=3620% times 5 = 100% text{ , so the number is } 7.2 times 5 = 36

Q4 :

The population of a town increased from 70,000 to 71,050. Find the increase per cent.

A
  

3%

B
  

2%

C
  

2.5%

D
  

1.5%

View Answer
Correct Answer: D

1.5%

Description:

 Increase %=105070,000×100=1.5%text{ Increase } % = frac{1050}{70,000} times 100 = 1.5%

Q5 :

A cask containing 425 litres, lost 8% by leakage. How many litres were left in the cask?

A
  

401

B
  

391

C
  

371

D
  

34

View Answer
Correct Answer: B

391

Description:

8% of 425=425100×8=348% text{ of } 425 = frac{425}{100} times 8 = 34

= 425 - 34 = 391

Q6 :

If the price of coal be raised by 20%, find by how much percent a housewife must reduce her consumption of that article so as not to increase her expenditure.

A
  40%
B
  

3313%33frac{1}{3}%

C
  

1623%16frac{2}{3}%

D
  

10%

View Answer
Correct Answer: C

1623%16frac{2}{3}%

Description:

According to rule, reduction in consumption

=20100+20×100%=1623%= frac{20}{100+20} times 100% = 16frac{2}{3}%

Q7 :

In an examination 70% of the candidates passed in English, 65% in Mathematics, 27% failed in both subjects. What is the pass percentage?

A
  

23%

B
  

28%

C
  

62%

D
  

38%

View Answer
Correct Answer: C

62%

Description:

Candidates failing in English = 30%
Candidates failing in Maths = 35%
Candidates failing in Boths = 27%
Fail percentage = (30 + 35 - 27)% = 38%
therefore Pass % = 62%
 

Q8 :

At an election where there are two candidates only the candidate who gets 62 percent of the votes is elected by a majority of 144 votes. Find the total number of votes.

A
  

125

B
  

200

C
  

600

D
  

400

View Answer
Correct Answer: C

600

Description:

One candidate got 62% of total votes, the other got 38%, so difference is 24%
therefore 24% of total votes = 144

 Total votes =144×10024=600therefore text{ Total votes } =144 times frac{100}{24} = 600

Q9 :

Two numbers are respectively 20% and 50% more than a third number. What percentage is the first of the third?

A
  

150

B
  

80

C
  

120

D
  

100

View Answer
Correct Answer: C

120

Description:

Let the third number 100, so the first is 120 and the second is 150. Thus first is 120 of third.

Q10 :

In an examination, 1000 were boys and 800 were girls, 60% boys and 40% of girls passed. The percentage of candidates that failed is

A
  

45.88

B
  

46.88

C
  

47.88

D
  

48.88

View Answer
Correct Answer: D

48.88

Description:

Candidates passing

= 60% ×times 1000 + 40% ×times 800

= 600 + 320 = 920

Total number  = 1000 + 800 = 1800

therefore  Pass %  =9201800×100=48.88=frac{920}{1800} times 100 = 48.88

Failed %  = 100 - 51.12 = 48.88

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