Profit and Loss Questions Answers

On every 9 pens, there is a gain of one pen, so gain $\mathrm{\%}=\frac{1}{9}\times 100=11\frac{1}{9}\mathrm{\%}$

Price after first discount
= 90% of Rs. 150 = Rs. 135

Price after second discount
= Rs. 135 - 5% of Rs. 135 = Rs. 128.25

125% C.P. = Rs. 4.25

$therefore$  C.P. of tea per kg = $frac{4.25 times 100}{125} = text{ Rs. } 3.40$

Gain on 1 kg  = 85 P.

Quantity of tea sold to recover 85 P when gain is 17 P per kg = 85 + 17 = 5 kg

S. P. of 80 kg = C.P. of 80 kg − S.P. of 20 kg

$Rightarrow$ S.P. of 100 kg = Rs. 88

$therefore$ S.P. of 1 kg = 88 P.

Reduced price of 4kg = 20% of Rs. 80 = Rs. 16
$therefore$  Reduced price per kg = Rs. 4
 

S.P. of the article = 60% of Rs. 120 = Rs. 72

Difference = Rs. 80 - Rs. 72 = 8

$therefore text{ Loss }$

5 mangoes + 4 oranges = 3 mangoes +  7 oranges

$Rightarrow$ 2 mangoes = 3 oranges $Rightarrow$ 3 : 2

S. P. of both = 2 $times$ 990 = 1980

Since in such situation there is always 1%  loss.

$therefore$ 99% of C.P.  = Rs. 1980

C.P. = Rs. 2000

$= frac{1}{2} text{ S.P.} = 87frac{1}{2}$

$therefore text{ S.P. } = 2 times 87frac{1}{2}$

$therefore$ Article should sold at 75% profit

Suppose C.P. of 10 articles = Rs. 10
$therefore$ S.P. of  9 articles = Rs. 10
$Rightarrow text{ S.P. of 10 articles } = frac{10 times 10}{9} =text{ Rs. } frac{100}{9}$
$therefore text{ Profit } = frac{100}{9} - 10 = frac{10}{9}$
$text{ Profit$