Time and Work Questions Answers

Work done by A and B in 8 min

$= 8 times Big(frac{1}{24} + frac{1}{30} Big) = 8 times Big(frac{5 + 4}{120} Big) = frac{9}{15} = frac{3}{5}$

$text{Remaining work } = 1 - frac{3}{5} = frac{2}{5}$

$frac{2}{5} text{ of the tank is filled by B in } frac{2}{5} times 30 = 12 text{ min}$

Tank filled in 2 hours = $frac{1}{4} + frac{1}{5} = frac{9}{20}$

Tank filled in 4 hours $= 2 times frac{9}{20} = frac{9}{10}$

Now $frac{1}{10}$  of the tank filled by A in

$Big(frac{1}{10} times 4 times 60 Big) text{min, i.e., 24 min.}$

Total time = 4 hrs. 24 min.

By question

$3text{W } = 2text{M} therefore 15text{M } = dfrac{3}{2} times 15 = dfrac{45}{2}text{W}$

$quad text{Women } quad text{Hours } quad text{Days }$

$because quad frac{45}{2} quadquadquad 8 quadquadquad 21$

$therefore quad 21 quadquadquad 6quadquad quad text{X}$

$therefore text{ X } = dfrac{21}{21} times dfrac{45}{2} times dfrac{8}{6} = 30 text{ days}$

Women required to sow 1 acre in 2 days = 15

$therefore$ Women required to sow 1 acre in 1 day = 15 x 2 = 30 women

So women required to sow 3 acres in one day = 30 x 3 =90 women